.17t^2-2t-4.4=0

Solution for .17t^2-2t-4.4=0 equation:

.17t^2-2t-4.4=0

a = .17; b = -2; c = -4.4;
Δ = b2-4ac
Δ = -22-4·.17·(-4.4)
Δ = 6.992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{6.992}}{2*.17}=\frac{2-\sqrt{6.992}}{0.34}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{6.992}}{2*.17}=\frac{2+\sqrt{6.992}}{0.34}
$